Which function has the smallest x-intercept value, if it exists? O f(x) = 3x – 9
O F(x) = +4
O f(x) = Vx+1
Of(x) = x²

The smallest x-intercept is x = -1, from equation 3.

Step-by-step explanation:

The x-intercept value of a function happens when "y", or in this case f(x), is equal to 0. Therefore we need to analyze each equation by making f(x) = 0 and finding x.

(a)

(b)

Since this is a constant function for which f(x) = 4, then there will be no x-intercept.

(c)

(d)

From these options the smallest x-intercept is x = -1.

dnji

step-by-step explanation:

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geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}