Write an equation of the line that passes through the point (5, -8) with slope 5

y=5x-33

Step-by-step explanation:

We are given a point and a slope. Use the slope-intercept formula.

where (x1, y1) is a point on the line and m is the slope.

The slope is 5 and the point is (5,-8).

x1=5

y1= -8

m=5

We want to find the equation of the line, which is y=mx+b (m is the slope and b is the y-intercept). Therefore, we must get y by itself on one side of the equation.

First, distribute the 5 on the right side of the equation. Multiply each term inside the parentheses by 5.

Next, subtract 8 from both sides since it is being added on to y.

The equation of the line is: y=5x-33

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)

3 qrs + 3/2 xy hope this : /

step-by-step explanation: