My boss has told me that I will need one gallon of paint for every 300 square feet of wall I must paint. Unfortunately, the store only sells cans containing 4 liters of paint, and our client has told me that she needs 400 square meters of wall painted. One liter contains approximately 0.264 gallons, and there are approximately 3.28 feet in a meter. What is the smallest number of cans of paint I can buy to complete the paint job?

14 cans

Step-by-step explanation:

Given, Total area to paint = 400 square meters

approximately 3.28 feet in a meter.

So, 400 square meters = 400 x (3.28)² square feet

i.e. Total area to paint  = 4303.36 square feet

One gallon of paint requires for every 300 square feet.

One liter contains approximately 0.264 gallons

Then, One gallon =

So, 3.78 liters paint requires for every 300 square feet.

Paint requires for each square feet = (3.78)÷(300) liters

Total paint required  = (Total area to paint ) x (Paint requires for each square feet)

= (4303.36)x (3.78)÷(300)

≈54.22 liters

Each can contains 4 liters of paint.

Smallest number of cans required = (Total paint required )÷ 4

=(54.22 ) ÷ 4

= 13.55≈ 14

Hence, 14 cans are required .

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo