AD= 36 cm. Points C, B∈AD, such that AB:BC:CD=2:3:4. Find the distance of midpoints of the segments AB and CD.

The distance of the midpoint of AB = 4 cm

The distance of the midpoint of CD = 28 cm

Step-by-step explanation:

The given information are;

Segment AD = 36

Point C and point B are points on AD such that AB:BC:CD = 2:3:4

Which gives;

The proportion of AB in AD = 2/(2+3+4) = 2/9

The length of AB = 2/9×36 = 8 cm

The proportion of BC in AD = 3/(2+3+4) = 3/9

The length of AD = 3/9×36 = 12 cm

The proportion of CD in AD = 3/(2+3+4) = 4/9

The length of AD = 4/9×36 = 16 cm

The coordinate of the midpoint of AB = 8/2 = 4 cm from A

The distance of the midpoint of AB = 4 cm

The coordinate of the midpoint of CD = 8 + 12 + 16/2 = 28 cm from A

The distance of the midpoint of CD = 28 cm.

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft