The width of an arch is 1.4 m and the semicircle at the top begins at a height of 1.9 m. What is the minimum amount of material in square metres needed to cover the whole arch so you cannot see through it?

The minimum amount of material in m^2 that will be needed to cover the whole arc will be 3.43 m^2

Step-by-step explanation:

This arc can be divide into two shape; a semi circle with a diameter of 1.9 m, and a rectangle with a width 1.9 m and a height of 1.4 m

For the semicircle, the area = ÷ 2

where d is the diameter

==> ÷ 2

==> 1.539 ÷ 2 = 0.7695 m^2

For the rectangle, area = width x height

==> 1.4 x 1.9 = 2.66 m^2

Total area = 0.7695 + 2.66 = 3.43 m^2

This is the minimum amount of material that will be needed to cover the whole arc.

add an image, and i will answer

step-by-step explanation:

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral