Plz Help, and solve. Show your work. I will give Brainliest. A - 7 = -13 solve and show your work 10X - 8 = 9X + 8 Can a right triangle have sides that measure 12, 16, and 20? Show your work and answer.

A - 7 = -13

Add 7

A = -6

10X - 8 = 9X + 8

Add 8

10X = 9X + 16

Subtract 9X

X = 16

In a right triangle, where a and b are the shorter sides, and c is the longer side a^2+b^2=c^2

Thus, plug in the values.

12^2+16^2=20^2

144+256=400

400=400.

Because the equation is true, 12, 16, and 20 can be a right triangle

Hope it helps <3

For the first question/equation, A=-6. You can just add seven on both sides.

A-7+7=-13+7          A=-6

For the second question, X=16. You can minus 9x on both sides, then plus 8 on both sides. 10X-9X-8+8=9X-9X+8+8=X=16

For the last one, yes, it can because of 12^2+16^2=20^2. Which simplified is . 144+256= 400. So, yeah. It can be a right triangle.

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq

don't report but were is the digram

step-by-step explanation: