Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). With Upper H1: p≠0.377, the test statistic is z=3.06. a. 0.0022; fail to reject the null hypothesis
b. 0.0011; reject the null hypothesis
c. 0.0022; reject the null hypothesis
d. 0.0011; fail to reject the null hypothesis

Option c: 0.0022; reject the null hypothesis

Step-by-step explanation:

Using a p value calculator, with a z score of 3.06 at 0.05 level of significance for a two tailed test, the p-value is 0.002213. This value is lower than 0.05 thus the result is significant we will reject the null hypothesis.

To calculate the p value by hand, we do this

The test statistic is 3.06. Since the test possesses a not equal to alternative, we look up the test statistic on the z table find the corresponding probability. Thus we have 3.06 - on the z table - 0.99889

Then we subtract from 1 and double it

1-0.99889 = 0.00111 x 2 = 0.0022.

idk

step-by-step explanation: