You weigh six packages and find the weights to be 26, 18,58,22,54,and 50 ounces. If you include a package that weighs 66 ounces, which will increase more, the median or the mean?

Step-by-step explanation:

The mean which is also known as the average is determined by dividing the sum of the weight of the packages by the total number of packages. From the information given,

Mean = (26 + 18 + 58 + 22 + 54 + 50)/6 = 38

If you include a package that weighs 66 ounces, the new mean would be

New mean = (26 + 18 + 58 + 22 + 54 + 50 + 66)/7 = 42

For the median, we would rearrange the weights in ascending order. It becomes

18, 22, 26, 50, 54, 58

Median = (26 + 50)/2 = 38

By adding the new weight, it becomes

18, 22, 26, 50, 54, 58, 66

New median = 50

It can be seen that both the median increased by more. It increased by 12 while the mean increased by 4

step-by-step explanation:

i could only see the first page. the other pages were blurry. ; -;

x hot dogs for 2$, y drinks for 3$. 29 items and total 70

2x+3y=70

x+y=29

if x=17and y=12

2(17)+3(12)=70

34+36=70

37

step-by-step explanation: