If you graph the system of Inequalities given below, which points would lie in the solution set? Select all the correct answers. x-y2-4
2x-ys 5
2y+ x>1

(-1,3)

Step-by-step explanation:

we need to replace the values x and y for every point and see if the point satisfies all the inequations.

Point (-2,3):

x - y ≥ -4

-2 - 3 ≥ -4

-5 ≥ -4

Then, -5 is not greater than -4, so that point is not a solution.

Point (-1,3):

x - y ≥ 4                      2x - y ≤ 5                2y + x > 1

-1 - 3 ≥ 4                     2(-1) - 3 ≤ 5             2(3) + (-1) > 1

-4 ≥ -4                        -5 ≤ 5                            5 > 1

Then, (-1,3) is a solution

Point (0,0):

x - y ≥ 4                      2x - y ≤ 5                2y + x > 1

0 - 0 ≥ 4                      2(0) - 0 ≤ 5             2(0) + (0) > 1

0 ≥ -4                           0 ≤ 5                            0 > 1

Then, 0 is not greater than 1, so that point is not a solution.

Point (2,-2):

x - y ≥ 4                      2x - y ≤ 5              

2 - (-2) ≥ 4                  2(2) - (-2) ≤ 5          

4 ≥ -4                           6 ≤ 5                    

Then, 5 is not greater than 6, so that point is not a solution.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

table 3 represents a direct variation function. : )