In a game, one player throws two fair, six-sided die at the same time. If the player receives a five or a one on either die, that player wins. What is the probability that a player wins after playing the game once

probability that a player wins after playing the game once = 5/9

Step-by-step explanation:

To solve this, we will find the probability of the opposite event which in this case, it's probability of not winning and subtract it from 1.

Since, we are told that there are 2 fair six sided die thrown at the same time and that he receives a five or a one on either die ;

Probability of not winning, P(not win) = 4/6.

Thus;

P(winning) = 1 - ((4/6) × (4/6))

P(winning) = 1 - 4/9 = 5/9

3. parallelogram

step-by-step explanation:

we turn each of our sides into direction vectors

ab=b-a=(3 - 7, 1 - 0) = (-4, 1)

bc=c-b=(1,6)

cd=d-c=(4,-1)

da=a-d=(-1,-6)

we see how the opposite sides have negated direction vectors; this is characteristic of a parallelogram.   we have congruent sides ab=cd and bc=da with unequal lengths because 1^2+6^2 is different from (-4)^2+1^2.   so it's not a square or a rhombus.  

we check the dot product of direction vectors of adjacent sides.   we have

ab dot bc = -4(1) + 1(6) = 2

that's not zero so the sides are not perpendicular.   we've ruled out rectangle.

the direction vectors indicate two pairs of congruent parallel sides, so we choose parallelogram over trapezoid.

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation: