What is the equation of the following line written in slope-intercept form?

Step-by-step explanation:

Line equation is given as y = mx + b

Where, m is the slope of the line, which is,

b is the y-intercept. It is the point at which the line crosses the y-axis for which the value of x = 0.

=>Find m and b to derive an equation for the line.

using the 2 coordinate pairs, (1, 5), (-1, -5),

Let, x2 = -1,

x1 = 1,

y2 = -5,

y1 = 5

From the graph given, the line intercepts the y-axis at point 0. Therefore b = 0.

Plug in the values of m and b in the line of equation.

y = mx + b

y = 5x + 0

y = 5x

Therefore, the equation of the line, in the graph above, written in slope-intercept form is:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl