find the zeros or x-intercepts (values of r and s) of a quadratic relation y=x^2-5x+6 by factoring using the sum and product method

And for this case we want to find the zeros or x interceps r and s so we want to rewrite the function on this way:

The reason why we have two zeros is because the degree of the polynomial is 2. If we find two numbers that adding we got -5 and multiplied 6 we solve the problem. For this case the solution is r =3, s =2

Step-by-step explanation:

For this problem we have the following polynomial given:

And for this case we want to find the zeros or x interceps r and s so we want to rewrite the function on this way:

The reason why we have two zeros is because the degree of the polynomial is 2. If we find two numbers that adding we got -5 and multiplied 6 we solve the problem. For this case the solution is r =3, s =2

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step-by-step explanation:

24+x=y

step-by-step explanation: