Helps pls Three generous friends, each with some cash, redistribute their money as follows: Ami gives enough money to Jan and Toy to double the amount that each has. Jan then gives enough to Ami and Toy to double their amounts. Finally, Toy gives Ami and Jan enough to double their amounts. If Toy has $36 when they begin and $36 when they end, what is the total amount that all three friends have?

The total amount that all three friends have = $258

Step-by-step explanation:

Three friends: let their initial money be  Ami's money =A, Jan = B, Toy = C

Toy started with $36 and ended with same amount

C = $36

After Ami gives, She is left with= A-x

Jan becomes= 2B

Toy becomes= 2C = 2×36 = 72

After Jan gives, Jan is left with = 2B-y

Ami now has = 2(A-x)

Toy now has = 2(72) = 144

After Toy gives, Toy is left with= 144-z

Ami now has = 2(2)(A-x) = 4(A-x)

Jan now has = 2(2B-y)

Since Toy is left with $36 at the end:

36 = 144-z

z = 144-36 = 108

So Toy spent $108 to double his two other friend's money

Both Amy  and Jan had $108 in total when Toy had $144

Difference between the deductions across = $108

The total amount that all three friends have = 144+108

The total amount that all three friends have= $258

okay..i will pick 8!