Hii I need a help .
thank you

a) 4 : 1 : 10

b) 25 : 9 : 13

c) 18 : 11 : 3

d) 2000 : 20 : 1

Step-by-step explanation:

We are to put the values in the form a : b : c

a) 40 ml, 1/100 l, 0.1 l

Put them all in ml (1 l = 1000 ml)

40ml, 10 ml, 100 ml

Therefore:

40 : 10 : 100

In lowest terms, 4 : 1 : 10

b) 2 1/2 kg, 900 g, 1.3 kg

Put them all in grams, (1 kg = 1000 g):

2500 g, 900 g, 1300 g

Therefore:

2500 : 900 : 1300

In lowest terms, 25 : 9 : 13

c) 1.5 hrs, 55 minutes, 1/4 hrs

Put them all in minutes (1 hour = 60 minutes)

90 minutes, 55 minutes, 15 minutes

Therefore:

90 : 55 : 15

In lowest terms, 18 : 11 : 3

d) 60 cm, 6 mm, 0.03 cm

Put them all in mm (1 cm = 10 mm)

600 mm, 6 mm, 0.3 mm

Therefore:

600 : 6 : 0.3

In lowest terms, 2000 : 20 : 1  (Divide by 0.3 because a ratio cannot be decimal)

idk

step-by-step explanation:

i don't know

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.