When 12x² + kx + 3 and 3x³ + (3k + 2)x² + 28x +17
are divided by 3x + 2, their remainders are
...
Mathematics, 22.07.2020 14:01 pearljammarow6ujs
When 12x² + kx + 3 and 3x³ + (3k + 2)x² + 28x +17
are divided by 3x + 2, their remainders are
equal. Find the value of the constant k.
Answers: 3
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