2/7/10 Container X contained 1200 g of sand. Container Y contained L
rand. After an equal amount of sand was removed from each com
Lontainer y now hos 7 times as much sand as Container XHOW now
and was removed from each container? Give your answer in kilograma

Complete question:

Container x contained 1200g of sand. Container y contained 7.2kg of sand. After as equal amount of sand was removed from each container, Container Ynow has 7 times as much as sand as container x. How much sand was removed from each container?

the mass of sand removed from both containers is 0.2kg

Step-by-step explanation:

Given that:

Mass of sand in container X = 1200g = 1.2kg

Mass of and in container Y = 7.2kg

Equal amount of sand was removed from both.

Let the mass of sand removed from both containers = z

That is;

Container X = 1.2 - z

Container Y = 7.2 -z

Now container Y has become 7times the content in container X

Container Y = 7 * (container X)

7.2 -z = 7(1.2 - z)

7.2 - z = 8.4 -7z

-z + 7z = 8.4 - 7.2

6z = 1.2

z = 0.2

Therefore, the mass of sand removed from both containers is 0.2kg

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

step-by-step explanation:

you can add the two numbers and divide the result by 2. or you can find the gap between the two numbers and add half of this to the smaller number.