A family has four children whose gender is unknown. If we randomly select one child from this family and find out that she is a girl, what is the probability that she is the only girl in this family

1/4

Step-by-step explanation:

We have a family where there are 4 children

The probability of having a girl child = 1/2

The probability of having a boy child = 1/2

Since each child has an equal chance of ending up as a boy or girl

The number of possible outcomes =

1/2 × 1/2 × 1/2 × 1/2 = 1/16

The probability of having a girl that is the only girl in this family = 4 ways

1) bbbg = 3 boys and 1 girl

2) bbgb = 2 boys, 1 girl, 1 boy

3) bgbb = 1 boy, 1 girl, 2 boys

4) gbbb = 1 girl, 3 boys

The probability to have a girl that is the only girl in the family = No of ways × No of possible outcomes

4 ways × 1/16

= 4/16 = 1/4.

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )