Use the definition of continuity and the properties of limit to show that the function f(x)=x sqrtx/ (x-6)^2 is continuous at x=36.

The function is continuous at x = 36.

Step-by-step explanation:

We need to follow the following steps:

The function is:

The function is continuous at point x=36 if:

Therefore:

The value of the function at x = 36 is:

The limit of the is the same at both sides of x=36, that is, the evaluation of the limit for values coming below x = 36, or 33, 34, 35.5, 35.9, 35.99999 is the same that the limit for values coming above x = 36, or 38, 37, 36.5, 36.1, 36.01, 36.001, 36.0001, etc.

For this case:

Since

And

Then, the function is continuous at x = 36.

if a = 1,   and b = 2, then the answer is 47.99999999. if you round that to the nearest whole number, the answer is 48.

step-by-step explanation:

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