The diameter of ball bearings produced in a manufacturing process can be explained using a uniform distribution over the interval 3.5 to 4.75 millimeters. What is the probability that a randomly selected ball bearing has a diameter greater than 4.4 millimeters?

The probability is 0.28

Step-by-step explanation:

Here, we want to calculate the probability that the ball bearing randomly selected has a diameter greater then 4.4 mm

I.e P(X> 4.4)

P(X>4.4) = (4.75-4.4)/(4.75-3.5) = 0.35/1.25 = 0.28

(f - g)(x) = 5x^3 - 3

step-by-step explanation:

rearrange these functions vertically, with like terms in separate columns:

f(x) = 5x^3 - 2

g(x) =         +1

now subtract, column by column:

(f - g)(x) = 5x^3 - 3