Suppose you computed a 95% confidence interval for the difference in mean weight between two species of snakes in a large nature reserve (species #1 – species #2), and your interval is –3.6 to 61.6 ounces. What can you conclude?

1. In a situation were we are willing to use 90% confidence, this means we could say that the observed difference that we have in the sample means tend to represents a real difference in the population means.

2. We cannot actually say because even with 95% confidence, that is the observed difference in sample means tend to as well represents a real difference in the population means.

3. Because the interval extends further in the positive direction than the negative direction this means that the evidence suggests that species #1 tend to weighs more than species #2 on average, but we can't actually say for sure.

Step-by-step explanation:

The following are what I will conclude about based on the information given in the question.

1. In a situation were we are willing to use 90% confidence, this means we could say that the observed difference that we have in the sample means tend to represents a real difference in the population means.

2. We cannot actually say because even with 95% confidence, that is the observed difference in sample means tend to as well represents a real difference in the population means.

3. Because the interval extends further in the positive direction than the negative direction this means that the evidence suggests that species #1 tend to weighs more than species #2 on average, but we can't actually say for sure.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18