What is the standard form of the equation for this circle? A (x-1)2-(y + 10)² + 4 = 0
B. (x - 1)2 - +10)2 = 2
c. (x + 1)2 + (y- 1072 = 4
D. (x-1)2-(y + 10)² =

(x + 1)² + (y - 10)² = 4

Step-by-step explanation:

Standard form of the equation of a circle is given by,

(x - h)² + (y - k)² = r²

where (h, k) is the center of the circle and 'r' is the radius.

In the given question coordinates of the center A are (-1, 10) and radius of the circle is 2 units.

By substituting these values in the formula,

(x + 1)² + (y - 10)² = 2²

(x + 1)² + (y - 10)² = 4

Therefore, standard form of the equation of the given circle is (x + 1)² + (y - 10)² = 4