find the odds in favor of drawing a red marble whyen a marble is selected at random from a bag containing 2 yellow, 5 red and 6 green marbles

The odd in favor of drawing a red marble is 5:8

Step-by-step explanation:

Let’s calculate the probability of selecting a red marble

That would be;

number of red marbles/Total number of marbles

Total number of marbles = 2 + 5 + 6 = 13

So the probability of drawing a red marble is 5/13

The probability of not drawing a red marble = 1-5/13 = 8/13

So the odd in favor of drawing a red marble is 5:8

idk

step-by-step explanation:

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)