A random sample of 51 adult coyotes in a region of northern Minnesota showed the average age to be x = 2.03 years, with sample standard deviation s = 0.82 years. However, it is thought that the overall population mean age of coyotes is μ = 1.75. Do the sample data indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years? Use α = 0.01.

Yes the sample data   indicate that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years

Step-by-step explanation:

From the question we are told that

   The sample size is  

    The sample mean is  

    The sample standard deviation is  

    The population mean is  

    The level of significance is  

The null hypothesis  is  

The alternative hypothesis is

The critical value of the the level significance obtained from the critical value table for z-value is

 Now the test statistic is mathematically evaluated as

substituting values  

From that calculated and obtained value we see that the critical value of the level of significance is less than the test statistics so we  reject the null hypothesis

Hence there sufficient evidence to proof that the sample data indicates that coyotes in this region of northern Minnesota tend to live longer than the average of 1.75 years

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x