1 - Fill the space blanks If we make a sequence selecting three elements from three different elements

{1, 2, 3} and we permit overlapped elements for the sequence, then the total

number of sequences is [ ] . If we do not take into account the order, the total

number of the selections is [ ] .

I'm totally lost in this, what is overlapped elements? This is about what math content? And what is the answer? Please i need help.

The first part is of permutations.

We are selecting 3 elements from three different elements {1,2,3}

Points given:

We permit overlapped elements for the sequence. Here "overlapped elements" indicates that repetition is allowed.

So when repetition is allowed and order matters, we use permutations.

Formula to compute permutation is:

Lets say n is the three elements {1,2,3}

We have to select 3 elements so r = 3

Total number of selections using permutations = =  n × n × n

                                                                    = 3³ = 3 * 3 * 3

                                                                    = 27

This means if we have 3 different elements then we have have 3 choices each time for making a sequence.

Hence  If we make a sequence selecting three elements from three different elements  {1, 2, 3} and we permit overlapped elements for the sequence, then the total  number of sequences is 27.

Step-by-step explanation:

The second part indicates combinations.

This is because the statement of the question:  If we do not take into account the order.

When the order does not matter, we use combinations.

So when the order does not matter and repetition is allowed we use the following formula:

Total number of selections using combinations = (r + n - 1)! / r! (n - 1)!

                                                                                = (3 + 3 - 1) ! / 3! (3 - 1)!

                                                                                = (3 + 2) ! / 3! (2!)

                                                                                = 5! / 3! 2!

                                                                                = 5*4*3*2*1 / (3*2*1 ) (2*1)

                                                                                = 120 / 6 * 2

                                                                                = 120 / 12

                                                                                = 10

So these are the number of combinations of 3 elements taken 3 at a time with  repetition.

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step-by-step explanation:

i hope this : )

answer

false

explanation

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