Ardem has two lights one flashes every 15 seconds the other flashes every 42 seconds. They start flashing at the same time. After how many seconds will they next flash at the same time??

After 210 seconds they with next flash at the same time.

Step-by-step explanation:

Given: Ardem has two lights.

One flashes every 15 seconds the other flashes every 42 seconds.

If they started flashing at the same time, then the number of seconds after that they with next flash at the same time = LCM (15, 42)   [LCM - Least common multiple]

Prime factorization of 15 = 3 x 5

Prime factorization of 42 = 2 x 3 x 7

Then, LCM (15, 42) = 2 x 3 x 5 x 7 = 210

i.e. After 210 seconds they with next flash at the same time.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

12m

step-by-step explanation:

square root means have of a number so have of 3 is 1.5 then multiply it by 8 and you get your answer!