the point slope form of the equation of the line that passes through (-5,1 ) and (10,-7) is y +7= - 1/2 (x-10) what is the standard form of the equation for this line ?

The standard form of the equation is y = -x/2 -2

Step-by-step explanation:

The standard form of equation of this line is expressing the line in the form;

y = mx + c

So let’s make a rearrangement to what we have at hand;

y + 7 = -1/2(x-10)

2(y + 7) = -1(x-10)

2y + 14 = -x + 10

2y = -x + 10 -14

2y = -x -4

divide through by 2

y = -x/2 -2

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)