Find the area of the triangle.

17.7 cm^2

Step-by-step explanation:

Use trig to find the height of the triangle. Then the area is bh/2.

Extend side BC to the right until it is vertically below point A. Draw a segment from point A vertically down until it intersects the extension of side BC. Call the point of intersection D. <D is a right angle.

Use triangle ABD to find the height, AD, of triangle ABC.

For <B of 37 deg, AD is the opposite leg. AB is the hypotenuse. The trig ratio that relates the opposite lefg to the hypotenuse is the sine.

sin B = opp/hyp

sin 37 deg = AD/13.1

AD = 13.1 * sin 37 deg

AD = 7.9

AD is the height of triangle ABC. BC is the base. We can find the area of triangle ABC.

area = bh/2

area = (4.5 cm)(7.9 cm)/2

area = 17.7 cm^2

.there can be infinite values of m and n that can satisfy the above equation. for each value of m of m or n. there maybe infinite sets of solution for the above

step-by-step explanation: