What is the solution of x = 2 + StartRoot x minus 2 EndRoot? A. x = 2 B. x = 3 C. x = 2 or x = 3 D. no solution

x = 2 or x = 3

Step-by-step explanation:

we have the expression:

First we must remove the square root, for this we pass the 2 to the left:

and we move the square root to the left as an exponent of two:

We develop the square binomial:

and clear the right side for the equation to be equal to zero:

combining like terms:

Because it is a quadratic equation we will have two answers, which we can find by the general formula or by factoring:

To factor we open two parenthesis, both with an x, and look for two numbers that when multiplied result in +6 and when added result in -5, those numbers are -2 and -3, so the factoring is:

And now we use the Zero Product Property, whic is if two thing are multiplied and result in zero one of the two or both things must zero, in this case:

and

the solutions are: x = 2 or x = 3; both satisfy the equation.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )