(3a^3-5b^3)+blank a^3+blank b^3=(a^3+b^3)

(3a³-5b³)+ (-2)a³ +6b³=(a³+b³)

Step-by-step explanation:

First,  lets remove the brackets.  There is no "-" before the brackets, so we can just remove them at all.

3a³-5b³+ ...a³ +...b³=a³+b³

Now we can joint similar monoms (with variable a)  ( and with variable b) in the left side of equation

3a³+...a³ -5b³ +...b³=a³+b³

Now we can notice that 3a³+...a³=a³    (1)  and

-5b³ +...b³=b³    (2)

Lets find deduct 3a³ from both sides of (1)

...a³= a³-3a³

...a³= -2a³  So instead ... we have to type -2 (-2 is negative sowe type -2 in brackets).

Similarly   lets add 5b³ to both sides of (2)

-5b³ +...b³=b³

-5b³ +5b³ +...b³=b³+5b³

...b³=6b³ So instead ... we have to type 6.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

a.)the line for function b is steeper