Problem number 26 of the Rhind Papyrus says: Find a quantity such that when it is added to StartFraction 1 Over 4 EndFraction of itself the result is a 15. The modern day equation that models this problem is x plus StartFraction 1 over 4 EndFraction x equals 15..

THIS IS THE COMPLETE QUESTION BELOW

Problem number 26 of the Rhind Papyrus says:

Find a quantity such that when it is added to ¼ of itself the result is 15.

The modern day equation that models this problem is x +

¼x = 15. What is the solution to the equation?

A) x = 10

B) x = 12

C) x = 15

D) x = 30

The quantity is X= 12

The solution is 12+ ¼(12)= 15

Step by step Explanation

Problem number 26 states " "

The question above can be represented as this,

x + ¼x = 15

Here we want to find the value of x in such a way that when that value is substitute in the expresion we have 15 as our answer,But here we can perform some manipulation, by saying

4/4x + ¼x = 15 eqn(1)

Even with this we can still get the above expression by saying

4/4x= x which means we're still correct.

Then the expresion eqn(1) can simplified as

5/4x = 15

If we multiply both sides by 4/5 we have

=(5/4x)×(4/5)

= 15×(4/5)

= (15/1)×(4/5)

X= 60/5

X = 12

The quantity is X= 12 and the solution is

12+ ¼(12)= 15

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

step-by-step explanation: