A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12}. Find the probability of rolling a number greater than 10

1/6

Step-by-step explanation:

There are 12 equally likely outcomes, so the total number of possible outcomes is 12.

There are 2 numbers greater than 10: 11 and 12.

The number of desired outcomes is 2.

p(event) = (number of desired outcomes)/(total number of possible outcomes)

p(greater than 10) = 2/12 = 1/6

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!

hello,

as we don't know if g(x) is continue,

answer b

f(x)=2x²-8x+1=2(x²-4x+4)+1-8=2(x-2)²-7

vertex is (2,-7) ( a minimum since coefficient of x² is > 0)