Find the distance between a point (–7, –19) and a horizontal line at y = 3. Choices are in the attachment...

Explanation:

The distance we're after is the vertical distance from the point to the line. So we only care about the difference in y values from y = -19 to y = 3

You can count out the spaces or use subtraction along with absolute value

distance from P to Q = |P-Q|

distance from -19 to 3 = |-19-3|

distance from -19 to 3 = |-22|

distance from -19 to 3 = 22

The absolute value is to ensure the result is never negative.

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5