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Answer and Explanation

Since (x + 3)^2 => 0 for all x, the smallest value of the function P(x) would be 2

When (x + 3)^2 = 0

x = -3 and y value of P(x) would be 2 (because there’s a plus 2)

So the vertex of the minimum point is (-3,2).

A) Q(x) = (x + 3)^2 + 5

Vertex is (-3,5)

B) R(x) = (x + 3 - 6)^2 + 2

As the opposite happens when you’re transforming x value.

= (x - 3)^2 + 2

Vertex is (3,2)

C) S(x) = (x + 3 - 4) ^2 + 2 - 7

= (x - 1)^2 - 5

Vertex is (1,-5)

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