Please Answer Now Identify the function’s vertical asymptotes. h(x)=x-4/x^2-4 x = 2 x = 4 x = -2, x = 2 x = -4, x = 4

x = 2 and x = +2

Step-by-step explanation:

It's essential that you use parentheses to clarify what's happening here:

h(x)=x-4/x^2-4  =>  h(x)=(x-4) / (x^2-4)

We have vertical asymptotes at x values at which the denominator (x^2 - 4) is zero.  That would be x = 2 and x = +2.

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).