The isosceles triangle and the square shown here have the same area in square units. What is the height of the triangle, $h$, in terms of the side length of the square, $s$?

h = 2s

Step-by-step explanation:

Area of square is equal to the area of triangle in this question.

the area of the square is s²

the area of the triangle is *h*s

s²=   *h*s

s = *h

2s = h

hope that helps

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is only a line? i think so