The hypotenuse and a leg of a particular right triangle are $\sqrt{97}$ inches and 4 inches, respectively. The area of this triangle is what common fraction of a square foot?

1/8

Step-by-step explanation:

Hypotenuse = √97

One leg = 4

By Pythagoras theorem, second leg² = (√97)² - 4²

= 97 - 16 = 81

So second leg = 9

Area of triangle = 4 x 9 / 2 = 18 sq inch

One sq foot = 144 sq inch

So required fraction = 18/144 = 1/8

three-fourths of an hour

36÷48=0.75

0.75=