In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC. PLEASE HELP I CANT FIGURE THIS OUT AT ALL 50 POINTS AND MARKING U SMARTEST THING! The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC. Part A: Identify a pair of similar triangles. (2 points) Part B: Explain how you know the triangles from Part A are similar. Part C: If DB = 9 and DC = 4, find the length of segment DA. Show your work.

Part A. Draw a same triangle which is point A to point E.(Triangle that have the same length as point A to point B)

Part B. The triangle from part A are similar because the triangle ∆ADE and ∆ADB are combined to form an isosceles triangle which have 2 equal sides.

Part C. Apply Sine rule.

AD=DA=15.59#

<BAD=180°-60°(get from isoceles triangle)-90°=30°

AD/sin60°=BD/sin30°

AD=9/sin30°xsin60°

Hope this help!

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide

i saw this question before, dont know the asnwer srry

step-by-step explanation: