Quantos números de quatro algarismos distintos podemos formar com os algarismos 1, 2, 3, 4, 5 e 6? * 3 pontos
340
360
350
330

We can write 360 distinct passwords using the numbers 1, 2, 3, 4, 5, and 6.

We have to find how many passwords with 4 different digits can we write with the numbers 1, 2, 3, 4, 5, and 6.

Firstly, it must be known here that to calculate the above situation we have to use Permutation and not combination because here the order of the numbers in a password matter.

Since we are given six numbers (1, 2, 3, 4, 5, and 6) and have to make 4 different digits passwords.

Now, for first digit of the password, we have 6 possibilities (numbers from 1 to 6).

Similarly, for second digit of the password, we have 5 possibilities (because one number from 1 to 6 has been used above and it can't be repeated).

Similarly, for the third digit of the password, we have 4 possibilities (because two numbers from 1 to 6 have been used above and they can't be repeated).

Similarly, for the fourth digit of the password, we have 3 possibilities (because three numbers from 1 to 6 have been used above and they can't be repeated).

Step-by-step explanation:

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answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.