Help! thanks if u do :) help appreciated! :D

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▹ Answer

2) b = 9

3) c = 5

4) d = 5

5) e = 12

6) f = 10

7) g = 16

8) h =6

9) i = 4

10) j = 4

11) k =5

12) l = 7

13) m = 3

14) n = 7

15) o = 4

16) p = 15

17) q = 15

18) r = 12

19) s = 15

▹ Step-by-Step Explanation

2) b - 1 = 8 → 1 + 1 = crossed out 8 + 1 = 9 → b = 9

3) c + c = 10 → c has to be the same so, 5 + 5 = 10 → c = 5

4) d + 6 = 11 → 6 - 6 = crossed out 11 - 6 = 5 → d = 5

5) e - 5 = 7 → 5 + 5 = crossed out 7 + 5 = 12 → e = 12

6) f + f + f = 30 → f has to be the same so, 10 + 10 + 10 = 30 → f = 10

7)  1/2 g = 8 → 8 ÷ 1/2 = 16 → g = 16

8) 2h = 12 → 2 ÷ 2 = h 12 ÷ 2 = 6 → h = 6

9) i + 9 = 13 → 9 - 9 = crossed out 13 - 9 = 4 → i = 4

10) 14 - j = 10 → 14 - 10 = 4 10 - 10 = crossed out → j = 4

11) 3k = 15 → 3 ÷ 3 = k 15 ÷ 3 = 5 → k = 5

12) 11 - l = 4 → 11 - 4 = 7 4 - 4 = crossed out → l = 7

13) 2m - 1 = 5 → 5 - 1 = 4 → 2m = 4 → 4 ÷ 2 = 2 → m = 2

14) 2n + 1 = 15 → 15 - 1 = 14 → 2n = 14 → 14 ÷ 2 = 7 → n = 7

15) 6o = 24 → 24 ÷ 6 = 4 → o = 4

16) p ÷ 3 = 5 → 5 * 3 = 15 → p = 15

17) q ÷ 5 = 3 → 3 * 5 = 15 → q = 15

18) r + 4 = 16 → 4 - 4 = crossed out 16 - 4 = 12 → r = 12

19) 20 - s = 5 → 20 - 5 = 15 → s = 15

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

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step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v