PLZ NEED A PROFESSIONAL :( Which is the equation of a parabola with a directrix at y = 2 and a focus at (5, 0) .
y = one fourth(x − 5)2 + 1
y = one fourth(x + 1)2 − 5
y = −one fourth(x + 1)2 − 5
y = −one fourth(x − 5)2 + 1

Answer D (the fourth one)

Step-by-step explanation:

First, we need to set up a (y−k)^2=4p(x−h). After plugging in all of your values, you would get (x-5)^2=-4(y-1). Now, we need to solve in terms of y by dividing each side by the factors that don't contain the variable. Your final solution should be

for future students the answer is b

hope i

-lavira: )