Complete the square to rewrite y = x2 - 6x + 16 in vertex form. Then state whether the vertex is a maximum or minimum and give its coordinates.

y = x² + 6x + 16

= (x² + 6x + 9) - 9 + 16

= (x + 3)² + 7 ← vertex form

Therefore, vertex is (-3, 7) and since the coefficient of (x + 3)² is positive the vertex is a minimum.

the answer is 45 i just did it on oddesy ware