An auto weighing 2,500 pounds is on a street inclined at 10 with the horizontal. Find the force necessary to prevent the car from rolling down the hill.

1931.7N

Step-by-step explanation:

We are told in the question that :

An auto ( a car) weighs = 2500 pounds

It s inclined at n horizontal Ange of 10°

We are asked to find the force that would prevents it from rolling down the street.

Since the unit for Force = Newton or kgm/s²

Step 1

Convert Weight in pounds to kg

1 pound = 0.453592kg

2500 pounds =

2500 pounds × 0.453592kg

= 1133.981kg

Step 2

Find the force that would prevents it from rolling down the street.

Force = Mass × Acceleration due to gravity × sin θ

Acceleration due to gravity = 9.81m/s

Force = 1133.981kg × 9.81 × sin 10°

Force = 1931.7237321 N

Approximately = 1931.7N

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.