Suppose the following set of random numbers is being used to simulate the event of a basketball player making two free throws in a row. How should the
numbers be rearranged?
502666 346453 524366 387026 704473 775061 350054 771009
621563 762199
O A. 50266 63464 53524 36638 70267 04473 77506 13500 54771
00962 15637 62199
O B. 502 666 346 453 524 366 387 026 704 473 775 061 350 054 771
009 621 563 762 199
C. 50 26 66 34 64 53 52 43 66 38 70 26 70 44 73 77 50 61 35 00 54
77 10 09 62 15 63 76 21 99
D. 5026 6634 6453 5243 6638 7026 7044 7377 5061 3500 5477
1009 6215 6376 2199

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

in 1995, potato plants were taken into space aboard the space shuttle columbia.

step-by-step explanation:

363 square inches

step-by-step explanation:

surface area of a pyramid is b + 1/2ph

b is the area of the base: 11 x 11 = 121

p is the perimeter of the base: 11 + 11 + 11 + 11 = 44

h is the height of the pyramid: 11

121 + 1/2(44)(11)

121 + 242

363