As a prize for winning a contest, the contestant is blindfolded and allowed to draw 3 dollar bills one at a time out of an urn. The urn contains forty $1 bills and ten $100 bills. The urn is churned before each selection so that the selection would be at random. What is the probability that none of the $100 bills are selected

The probability that none of the $100 bills are selected is 79.6%.

Step-by-step explanation:

The urn contains forty $1 bills and ten $100 bills.  This gives a total of 50 bills in the urn.

To draw 3 dollar bills one at a time out of an urn, the probability of not selecting a $100 bill, decreases with each selection.

And the probability of not selecting a $100 bill is the probability of selecting a $1 bill in the first selection  = 80% (40/50 x 100).

The probability of selecting a $1 bill the second time = 79.6% (39/49).

The probability of selecting a $1 bill the third time = 79.2% (38/48).

The sum of the probabilities divided by 3 = 79.6% (238.8/3)

b) Probability arises when there is a chance that an event may occur from a set of events that could have occurred. It is based on an estimate that one event happens when all the events in the set are given no less equal chance.

need more detail

step-by-step explanation:

lele

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.