pl help Six friends, four boys and two girls, went to a movie theater. They wanted to sit in a way so no girl sits on either first or last chair. How many such arrangements are possible?

672 ways

Step-by-step explanation:

The total number of ways the friends were supposed to sit without restrictions would have been = 6!

= 720 possible ways.

If the girs should sit on the first or last sit

The possible arrangement= 2!4!

= 2*24

= 48

But now the two girls should be arranged in such a way that the don't sit on either the first or the last chair.

So the possible way now is= way without restriction - way if the girls are to sit at either first or last sit

= 720-48

= 672

your answer is 228

step-by-step explanation:

add the top and bottom bases together, then divide them by 2, then multiply by the height.