What is the true solution to the equation below? In e^Inx + In e^Inx2=2 In 8

John bought 5 lemons and used 2 of them for a salad how much did he use for.a salad . he used % of the lemons.

Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .

Which expression do you get when you eliminate the negative exponents of 4a^2 b^216a^-3 b