If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true? The figure must be an isosceles trapezoid because it has 2 congruent base angles. The figure must be a rectangle because all rectangles have exactly 2 lines of symmetry. The figure could be a rhombus because the 2 lines of symmetry bisect the angles. The figure could be a square because the diagonals of a square bisect the right angles.\\

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

the answer is stop cheating on things stoopid

step-by-step explanation:

im eatin up the 44

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

could u provide us some answer choices or hmm idk maybe a table for us to anser with ? ?