Which is the solution to the system of equations? y=1/3x+2 y=4/3x-5

x = 7 . y = 13/3

Step-by-step explanation:

Solve the following system:

{y = x/3 + 2

y = (4 x)/3 - 5

Express the system in standard form:

{-x/3 + y = 2

-(4 x)/3 + y = -5

Express the system in matrix form:

(-1/3 | 1

-4/3 | 1)(x

y) = (2

-5)

Write the system in augmented matrix form and use Gaussian elimination:

(-1/3 | 1 | 2

-4/3 | 1 | -5)

Swap row 1 with row 2:

(-4/3 | 1 | -5

-1/3 | 1 | 2)

Subtract 1/4 × (row 1) from row 2:

(-4/3 | 1 | -5

0 | 3/4 | 13/4)

Multiply row 1 by 3:

(-4 | 3 | -15

0 | 3/4 | 13/4)

Multiply row 2 by 4:

(-4 | 3 | -15

0 | 3 | 13)

Divide row 2 by 3:

(-4 | 3 | -15

0 | 1 | 13/3)

Subtract 3 × (row 2) from row 1:

(-4 | 0 | -28

0 | 1 | 13/3)

Divide row 1 by -4:

(1 | 0 | 7

0 | 1 | 13/3)

Collect results:

 {x = 7 . y = 13/3

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|

id

step-by-step explanation:

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