Directions: Use the acronym PANIC to find the confidenceintervals.1.An SRS of 60 women showed that the average weight of a purse is 5 pounds with a standard deviation of 1.2 pounds. Find the 90% Confidence Interval for the actual average weight of purses.

90% Confidence Interval for the actual average weight of purses.

(4.7412 , 5.2588)

Step-by-step explanation:

Explanation:-

Given sample size 'n' = 60

mean of the sample x⁻ = 5 pounds

Standard deviation of the sample 'S' = 1.2 pounds

Level of significance = 0.10

90% Confidence Interval for the actual average weight of purses.

( 5 - 0.2588 , 5 + 0.2588)

90% Confidence Interval for the actual average weight of purses.

(4.7412 , 5.2588)

i think the correct option is the second option.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier