Figure abcd is a rectangle. Find the value of EC

Step-by-step explanation:

Given: A rectangle ABCD in which diagonals AC and BD intersect at E.

AE = X + 11

CE = 6x + 1

To find: Find AC

solution,

The diagonals at a rectangle bisects each other. Hence, AE = EC

x + 11 = 6x + 1

Move the variable to L.H.S and change its sign

X - 6x + 11 = 1

Move the constant to R.H.S and change its sign

x - 6x = 1 - 11

Simplify

-5x = -10

Divide both side of the equation by 5

-5x/5 = -10/5

Calculate

-x = -2

The minus sign (-) will be cancelled on both sides

X = 2

Again,

EC = 6x + 1

= 6 * 2 + 1

= 12 + 1

= 13

Hope this helps...

Good luck on your assignment...

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870